The impossible pill riddle
posted by RiddleMeThis
- January 31 2015 08:16:16 AM
https://www.youtube.com/watch?v=gjTKHQ_IbRE
Reply by Paranoid
- April 14 2015 03:08:56 AM
1. Divide the pills in group of 3 3 2
2. Weight the groups of 3 pills
3. If equal, the heavier one is from the group of 2 and can be weighed individually -> Done!
4. Else, From the heavier group select two pills and weigh them. If not equal -> Done!
5. If equal, third one from the group is heavier-> Done!
2. Weight the groups of 3 pills
3. If equal, the heavier one is from the group of 2 and can be weighed individually -> Done!
4. Else, From the heavier group select two pills and weigh them. If not equal -> Done!
5. If equal, third one from the group is heavier-> Done!
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