330?

It can be written as the sum of 25-35
It can be written as the sum of 64-68
It can be written as the sum of 109-111

If you want to know how I calculated it, I'll be happy to elaborate in the next comment. Just in case you want to know.

Elaborate please

Keep writing this, or else you might get confused.

Let the 11 consecutive numbers be (x-5), (x-4).... (x).... (x+4), (x+5). On addition, they'll give you 11x. (Yes, I chose the numbers deliberately in such a manner, that they would conveniently cancel out.

Do the same for 5, and 3 consecutive numbers with y and z. You'll get 5y, and 3z.

Now all these represent the same number, i.e.
11x = 5y = 3z

Hence the number must be a common multiple of all three, 11, 5 and 3. That is 165. But the required number is even. So just multiply 165 with 2, and you get 330.
If you want, just equate this value with the above three equations, and you'll have the values of x, y and z.
Then the summations are from
1) (x-5) to (x+5)
2) (y-2) to (y+2)
3) (z-1) to (z+1)

And hence the problem is solved! :D

good logic,caprico

I agree

Thank you!